A group of girls shared some sweets among themselves. They tried taking 11 sweets each, but found that the last girl had only 6 sweets. When each girl took 8 sweets, there were 25 sweets left over. How many sweets were there altogether?
[ ] -- 1 u
[ ][ ][ ][ ][ ][ ][ ][ ][ ][ ][6][5]
[ ][ ][ ][ ][ ][ ][ ][ ][ 25 ]
3 u --> 25 + 5 = 30
1 u --> 30/3 = 10
11 u --> 11 x 10 = 110
110 - 5 = 105 sweets
There are 105 sweets.
Alternative method
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11 x (n - 1) + 6 --> 8 x n + 25
3 n --> 25 - 6 + 11 = 30
n --> 30/3 = 10
8 x 10 + 25 = 105 sweets
There are 105 sweets.
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To solve this question,is this acceptable in PSLE:
ReplyDelete8[25+(11-6)/(11-8)]+25= 105
Zero mark. The workings are wrong. There is a missing bracket.
ReplyDeleteAs appeared in PSLE 2010 exam:
ReplyDeleteA group of girls shared some sweets among themselves. They tried taking 11 sweets each, but found that the last girl had only 6 sweets. When each girl took 8 sweets, there were 25 sweets left over. How many sweets were there altogether?