Thursday, October 7, 2010

Area & Perimeter PSLE 2010 P2 Q4

In the figure below, AB=7 cm, BC=9 cm, CD=3 cm and DA=11 cm. Angle ABC and Angle CDA are right angles.















Find the area of the figure ABCD.


1/2 x  9 x 7  =  31.5


1/2 x 11 x 3  =  16.5


31.5  +  16.5  =  48  cm2

It is  48  cm2.
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  1. AnonymousJanuary 1, 2011 at 7:18 AM

    As appeared in PSLE 2010 exam:

    In the figure below, AB=7 cm, BC=9 cm, CD=3 cm and DA=11 cm. Angle ABC and Angle CDA are right angles.

    Find the area of the figure ABCD.

    ABCD is a 4-sided figure with base AD from left to right and is 11 cm. From A,it is joined to B and AB is 7 cm. From B, it is joined to C and BC is 9 cm. From C, it is joined to D and CD is 3 cm.

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