Thursday, October 7, 2010

Angle PSLE 2010 P2 Q9

9.  In the figure below, ABCD is a trapezium. E is a point on AD such that AB=BE. Angle BCD=62⁰ and angle CDE=110⁰
Find angle EBC.




180  -  110  =  70

180  -  70  -  70  =  40


180  -  62  =  118

118  -  40  =  78°


It is 78°.

1 comment:

  1. As appeared in PSLE 2010 exam:

    In the figure below, ABCD is a trapezium. E is a point on AD such that AB=BE. Angle BCD=62⁰ and angle CDE=110⁰
    Find angle EBC.

    Diagram showing an isosceles trangle ABE with AB=BE marked as equal.It's joined by a 4-sided figure BCDE to form a trapezium ABCD. A starts from the bottom left hand corner and goes clockwise direction to B,C,D,E and back to A.

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