Monday, October 4, 2010

Australian Mathematics Competition Junior Q26

An ascending number is one in which each successive digit is greater than the one before. Find the 3-digit descending number which is the square of an ascending number?


29  x  29  =  841 descending
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  1. AnonymousAugust 12, 2015 at 6:17 PM

    x2(xyz)+[2(x)2]=number more than 27 but less than 30
    Trial and error for 28 and 29 tells you that x is 29 hence answer is 29 squared=841
    which is correct! ;-)

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