Showing posts with label M Ratio P6 Rosyth. Show all posts
Showing posts with label M Ratio P6 Rosyth. Show all posts
Tuesday, September 27, 2011
Monday, May 23, 2011
Fraction P6 2010 SA1 Rosyth P2 Q18
There were 156 more pupils in the playground than in the library. 1/5 of the pupils in the library were girls and 5/6 of the pupils in the playground were boys. If there were 17 more girls in the playground than in the library, find the total number of pupils in the two places.
You may start with
a) There were 156 more pupils in the playground than in the library, or
b) there were 17 more girls in the playground than in the library
1/5 of the pupils in the library were girls --> 5 units in library with 1 unit girls
5/6 of the pupils in the playground were boys --> 6 UNITS in playground, with 1 UNIT girls
Note: unit and UNIT are not the same
a)
There were 156 more pupils in the playground than in the library
Draw 6 UNITS for playground + 156 [divided in 6 parts]
Draw 6 UNITS for library, but with 1 UNIT divided into 5 parts
P [ ][ ][ ][ ][ ][ ][][][][][][]
L [ ][ ][ ][ ][ ][||||]<---156--->
156 ÷ 6 = 26
Compare the girls in the playground and library
26 [ ][ ]
[ ][|
17
26 - 17 = 9
1 u --> 9 x 5 = 45 Compare the 6 UNITS of playground with 6 UNITS of libary
6 u --> 6 x 45 = 170
270 + 156 + 270 = 696 pupils
There were 696 pupils.
Alternative solution (b)
----------------------------
there were 17 more girls in the playground than in the library
[ ][17]
[ ]
[][17] [][17] [][17] [][17] [] [17] [][17]
[] [] [] [] [] <------------156------------>
6 u + 17 x 6 --> 5 u + 156
1 u --> 156 - 102 = 54
5 u --> 5 x 54 = 270
270 + 270 + 156 = 696 pupils
There were 696 pupils.
You may start with
a) There were 156 more pupils in the playground than in the library, or
b) there were 17 more girls in the playground than in the library
1/5 of the pupils in the library were girls --> 5 units in library with 1 unit girls
5/6 of the pupils in the playground were boys --> 6 UNITS in playground, with 1 UNIT girls
Note: unit and UNIT are not the same
a)
There were 156 more pupils in the playground than in the library
Draw 6 UNITS for playground + 156 [divided in 6 parts]
Draw 6 UNITS for library, but with 1 UNIT divided into 5 parts
P [ ][ ][ ][ ][ ][ ][][][][][][]
L [ ][ ][ ][ ][ ][||||]<---156--->
156 ÷ 6 = 26
Compare the girls in the playground and library
26 [ ][ ]
[ ][|
17
26 - 17 = 9
1 u --> 9 x 5 = 45 Compare the 6 UNITS of playground with 6 UNITS of libary
6 u --> 6 x 45 = 170
270 + 156 + 270 = 696 pupils
There were 696 pupils.
Alternative solution (b)
----------------------------
there were 17 more girls in the playground than in the library
[ ][17]
[ ]
[][17] [][17] [][17] [][17] [] [17] [][17]
[] [] [] [] [] <------------156------------>
6 u + 17 x 6 --> 5 u + 156
1 u --> 156 - 102 = 54
5 u --> 5 x 54 = 270
270 + 270 + 156 = 696 pupils
There were 696 pupils.
Friday, September 10, 2010
Rates P6 2010 SA2 Rosyth P2 Q16
Machine A and B each printed a fixed number of newspaper per hour. Machine B started printing earlier at a rate of 75 copies per hour. After Machine B had printed for 10 hours, Machine A had printed 340 copies. After Machine B had printed for 16 hours, Machine A had printed 886 copies. (a) How many copies of newspaper did Machine A print per hour? (b) How long would Machine B have worked when both machines have printed a total of 2750 copies? [5 marks][Answer given: 91 copies, 20 hours]
B1: 10 h --> 10 x 75 = 750 copies
A1: ? h --> 340 copies
B2: 16 h --> 16 x 75 = 1200 copies
A2: ? + 6 h --> 886 copies
A: 6 h --> 886 - 340 = 546 copies
1 h --> 546/6 = 91 copies
a) It was 91 copies.
A + B : 1 h --> 91 + 75 = 166 copies
2750 - 750 - 340 = 1660 copies
1660/166 = 10 h
10 + 10 = 20 h
b) It was 20 h.
B1: 10 h --> 10 x 75 = 750 copies
A1: ? h --> 340 copies
B2: 16 h --> 16 x 75 = 1200 copies
A2: ? + 6 h --> 886 copies
A: 6 h --> 886 - 340 = 546 copies
1 h --> 546/6 = 91 copies
a) It was 91 copies.
A + B : 1 h --> 91 + 75 = 166 copies
2750 - 750 - 340 = 1660 copies
1660/166 = 10 h
10 + 10 = 20 h
b) It was 20 h.
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