In the figure below, ABC is a triangle. X, Y and Z are points on the triangle such that AX=AY and YB=ZB.
If angle AYZ=104⁰ and angle XYB=107⁰, find angle ZCX.
180 - 104 = 76
180 - 76 - 76 = 38
180 - 107 = 73
180 - 73 - 73 = 34
180 - 28 - 34 = 118⁰
It is 118°.
Alternative solution provided by P6 pupil
107° + 104° = 211°
As appeared in PSLE 2010 exam:
ReplyDeleteIn the figure below, ABC is a triangle. X, Y and Z are points on the triangle such that AX=AY and YB=ZB.
If angle AYZ=104⁰ and angle XYB=107⁰, find angle ZCX.
Diagram given:
ABC is a triangle with A at the left hand corner and goes clockwise passing B, C and back to A. CB is the base.
X is a point along line AC and is joined to a point Y which is along the line AB.
Z is a point along CB and is joined to point Y.
Both AX and AY are marked as equal in length.
Both YB and BZ are marked as equal in length.
180-107=73
ReplyDelete180-104=76
180-73=107
180-76=104
180-76-73=31
Total angles in a 4sided figure equals to 360 degrees
360-104-107-31=118