Monday, April 5, 2010

Circle P6 2009 SA1 P2 RGS Q15

15. The figure is made up of 4 equal quadrants and one semicircle. AB = CD = EF = 8 cm. The total area of the unshaded parts is 33.5 cm2. Take π as 3.14.


a) Find the total perimeter of the shaded parts. [1]
b) Find the total area of the shaded parts. [4]


2 x 3.14 x 8 = 50.24

50.24 + 8 + 8 = 66.24 cm

a) The total perimeter of the shaded parts is 66.24 cm.


1/2 x 3.14 x 4 x 4 = 25.12

33.5 – 25.12 = 8.38

3.14 x 8 x 8 = 200.96

200.96 – 8.38 – 8.38 = 184.2 cm2


The total area of the shaded parts is 184.2 cm2.

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