4 men and 4 women are to be seated at a round table for dinner. If the men and women take alternate seats, how many arrangements are possible?
4 x 3 x 2 x 1 x 4 x 3 x 2 x 1 = 576 ways
The arrangement for men is 4 x 3 x 2 x 1 and the arrangement for women is also 4 x 3 x 2 x 1.
Showing posts with label M Mathlympics 2009. Show all posts
Showing posts with label M Mathlympics 2009. Show all posts
Friday, June 25, 2010
Annual Mathlympics 2009
Janice was given a set of 5 different coloured beads to make a bracelet.If she has to use all of the 5 beads, how many different ways can Janice make the bracelet?
5 x 4 x 3 x 2 x 1 / 2 = 60 ways
There are 5 ways to pick the first bead, 4 ways to pick the second bead, 3 ways to pick the third bead, 2 ways to pick the fourth bead and 1 way to pick the last bead. As the bracelet can be turn over, the arrangement ABCDE is the same as EDCBA. So the number of ways is halved.
5 x 4 x 3 x 2 x 1 / 2 = 60 ways
There are 5 ways to pick the first bead, 4 ways to pick the second bead, 3 ways to pick the third bead, 2 ways to pick the fourth bead and 1 way to pick the last bead. As the bracelet can be turn over, the arrangement ABCDE is the same as EDCBA. So the number of ways is halved.
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