Showing posts with label M P6 NY. Show all posts
Showing posts with label M P6 NY. Show all posts
Sunday, October 3, 2010
Volume P6 2010 SA2 Nanyang P2 Q 11
40 x 20 x 10 = 8000 Amount of water upto bottom of cube
12000 - 8000 = 4000 cm3 Amount of water from above bottom of cube
40 x 20 = 800
10 x 10 = 100
800 - 100 = 700 cm2 Area of water just above bottom of cube
4000 / 700 = 5.71 Height of water above bottom of cube
5.71 + 10 = 15.71 cm Height of water
It was 15.71 cm.
Decimal P6 2010 SA2 Nanyang P2 Q13
Quiny and Mandy saved $5748.40 altogether. 0.4 of Quiny’s savings was $431.50 more than 0.2 of Mandy’s savings. How much more money than Quiny did Mandy save? [4 marks][Answer given: $477.80]
Quiny's money --> 10 Q
Mandy's money --> 10M
4 Q --> 2 M + $431.50
2 M --> 4 Q - $431.50
10 M --> 20 Q - 5 x 431.50 = 20 Q - $2157.50
10 Q + 10 M --> $5748.40
30 Q --> 5748.40 + 2157.50 = 7509.90
10 Q --> 7509.90/3 = $2635.30
10 M --> 2 x 2635.30 - 2157.50 = $3113.10
10 M - 10 Q --> 3113.10 - 2635.30 = $477.80
It was $477.80.
Model Drawing
------------------
431.50 / 2 = $215..75 0.4 = 4/10 = 2/5
Compare 2 units of Q (total 5 units) with 2 units of M (total 10 units)
Q [][215.75][][ ][][ ][][ ][][ ] ] $5748.40
M [][][][][][][][][][] ]
215.75 x 5 = 1078.75
15 u --> 5748.40 - 431.50 = 4669.65
5 u --> 5/15 x 4669.75 = 1556.55
1078.75 - 1556.55 = $477.80
It was $477.80.
Quiny's money --> 10 Q
Mandy's money --> 10M
4 Q --> 2 M + $431.50
2 M --> 4 Q - $431.50
10 M --> 20 Q - 5 x 431.50 = 20 Q - $2157.50
10 Q + 10 M --> $5748.40
30 Q --> 5748.40 + 2157.50 = 7509.90
10 Q --> 7509.90/3 = $2635.30
10 M --> 2 x 2635.30 - 2157.50 = $3113.10
10 M - 10 Q --> 3113.10 - 2635.30 = $477.80
It was $477.80.
Model Drawing
------------------
431.50 / 2 = $215..75 0.4 = 4/10 = 2/5
Compare 2 units of Q (total 5 units) with 2 units of M (total 10 units)
Q [][215.75][][ ][][ ][][ ][][ ] ] $5748.40
M [][][][][][][][][][] ]
215.75 x 5 = 1078.75
15 u --> 5748.40 - 431.50 = 4669.65
5 u --> 5/15 x 4669.75 = 1556.55
1078.75 - 1556.55 = $477.80
It was $477.80.
Labels:
M Decimal P6,
M Decimal P6 NY,
M P6 NY
Challenging P6 2010 SA2 Nanyang P2 Q15
The table below shows the day of the week that 1st January falls on from the year 1981 to 2000. Note that Day 1 of a week is a Monday and Day 7 is Sunday. There are 31 days in the month of January.
a) What number does the letter C represent ? (Ans : 3)
b) What number does the letter F represent ? (Ans : 7)
c) Which day of the week will 1st February 2012 fall on ? (Ans : Wednesday)
2003 - 1981 = 22 years
22/4 = 5 leap years (max) Leap year --> 366 days
22 x 365 + 5 =8035 days Account for leap years
8035 + 4 = 8039 Since 1 Jan 1981 is 4 (Thursday).
8039/7 = 1148 r 3
a) It was 3.
2006 - 1981 = 25 years
25/4 = 6 leap years (max)
25 x 365 + 6 + 4 = 9135
9135/7 = 1305 or 1304 r 7 Need to express with a remainder
b) It was 7.
2012 - 1981 = 31 years
31/4 = 7 leap years (max)
31 x 365 + 31 + 7 + 4 = 11357 days
11357/7 = 1622 r 3
3 --> Wednesday
c) It is Wednesday.
Labels:
M Challenging P6,
M Challenging P6 NY,
M P6 NY
Fraction P6 2010 SA2 Nanyang P2 Q16
Mrs Reuten bought some pizzas for a group of children. The girls received thrice as many pizzas as the boys. There were an equal number of girls and boys. Each boy ate 2/9 of a pizza and the boys finished all the pizzas given to them. Each girl ate 1/6 of a pizza and the girls had 4½ pizzas left. How many pizzas did Mrs Reuten buy? [5 marks][Answer given: 8 pizzas]
2/9 : 1/6 = 4 : 3 Multiply by 18
G [][][][][][][][][][][][]
B [][][][]
9 u --> 4 1/2
16 u --> 16/9 x 9/2 = 8 pizzas
It was 8 pizzas.
2/9 : 1/6 = 4 : 3 Multiply by 18
G [][][][][][][][][][][][]
B [][][][]
9 u --> 4 1/2
16 u --> 16/9 x 9/2 = 8 pizzas
It was 8 pizzas.
Labels:
M Fraction P6,
M Fraction P6 NY,
M P6 NY
Ratio P6 2010 SA2 Nanyang P2 Q17
There were some blue marbles and white marbles in a bag. If 70 blue marbles were to be removed from the bag, the ratio of the number of blue marbles to the number of white marbles would be 3 : 4. If 112 white marbles were to be removed from the bag instead, the ratio of the number of blue marbles to the number of white marbles would be 8 : 7. When 48 more blue marbles were to be added into the bag, what percentage of all the marbles would be blue marbles? [5 marks][Answer given: 49.6%]
B W
- 70
--------------
3 : 4
--------------
4 B - 4 x 70 --> 3 W
4 B --> 3 W + 280
28 B -->: 21 W + 7 x 280 = 21 W + 1960
B W
- 112
---------------
8 : 7
---------------
7 B --> 8 W - 8 x 112 = 8 W - 896
28 B --> 32 W - 4 x 896 = 32 W - 3584
32 W - 3584 --> 21 W + 1960
11 W --> 1960 + 3584 = 5544
W --> 5544/11 = 504
4 B --> 3 x 504 + 280 = 1792
B --> 1792/4 = 448
448 + 48 = 496 blue marbles
496 + 504 = 1000
496/1000 x 100% = 49.6%
It was 49.6%.
Alternative method
----------------------
3 u + 70 --> 8 p
4 u - 112 --> 7 p
12 u --> 32 p - 4 x 70 = 32 p - 280
12 u --> 21 p + 3 x 112 = 21 p + 336
32 p - 280 --> 21 p + 336
11 p --> 336 + 280 = 616
1 p --> 616 / 11 = 46
8 p --> 8 x 56 = 448
448 + 48 = 496 blue marbles
15 p --> 15 x 56 = 840
840 + 112 + 48 = 1000 marbles
496/1000 x 100% = 49.6%
It was 49.6%.
B W
- 70
--------------
3 : 4
--------------
4 B - 4 x 70 --> 3 W
4 B --> 3 W + 280
28 B -->: 21 W + 7 x 280 = 21 W + 1960
B W
- 112
---------------
8 : 7
---------------
7 B --> 8 W - 8 x 112 = 8 W - 896
28 B --> 32 W - 4 x 896 = 32 W - 3584
32 W - 3584 --> 21 W + 1960
11 W --> 1960 + 3584 = 5544
W --> 5544/11 = 504
4 B --> 3 x 504 + 280 = 1792
B --> 1792/4 = 448
448 + 48 = 496 blue marbles
496 + 504 = 1000
496/1000 x 100% = 49.6%
It was 49.6%.
Alternative method
----------------------
3 u + 70 --> 8 p
4 u - 112 --> 7 p
12 u --> 32 p - 4 x 70 = 32 p - 280
12 u --> 21 p + 3 x 112 = 21 p + 336
32 p - 280 --> 21 p + 336
11 p --> 336 + 280 = 616
1 p --> 616 / 11 = 46
8 p --> 8 x 56 = 448
448 + 48 = 496 blue marbles
15 p --> 15 x 56 = 840
840 + 112 + 48 = 1000 marbles
496/1000 x 100% = 49.6%
It was 49.6%.
Labels:
M P6 NY,
M Percentage P6,
M Percentage P6 NY,
M Ratio P6,
M Ratio P6 NY
Circle P6 2010 SA2 Nanyang P2 Q18
18. The figure below is created using the curved lines (arcs) of quadrants with radius 1 cm, 2 cm and 3 cm. Find the area of the shaded parts.
(Take pi as 3.14)
Circle of radius 3 cm - 4 x Right-angled triangles of sides 3 cm -
[Circle of radius 1 cm - 4 x Right-angled triangles of sides 1 cm]
4 x Right-angled triangles = 1/2 x Diagonal x Diagonal
1/2 x 2 x 2 = 2
3.14 - 2 = 1.14
3.14 x 3 x 3 = 28.26
1/2 x 6 x 6 = 18
28.26 - 18 - 1.14 = 9.12 cm2
(Take pi as 3.14)
Circle of radius 3 cm - 4 x Right-angled triangles of sides 3 cm -
[Circle of radius 1 cm - 4 x Right-angled triangles of sides 1 cm]
4 x Right-angled triangles = 1/2 x Diagonal x Diagonal
3.14 x 1 x 1 = 3.14
1/2 x 2 x 2 = 2
3.14 - 2 = 1.14
3.14 x 3 x 3 = 28.26
1/2 x 6 x 6 = 18
28.26 - 18 - 1.14 = 9.12 cm2
It was 9.12 cm2.
Saturday, September 11, 2010
Ratio P6 2010 SA2 Nanyang P1 Q21
The cost of 3 mangoes is the same as the cost of 5 grapefruits. The cost of 3 mangoes is also the same as the cost of 10 pears. Find the ratio of the cost of a mango to the cost of a grapefruit to the cost of a pear.
(Ans : 10 : 6 : 3)
3 M --> 5 G
M/G --> 5/3 = 10/6
3 M --> 10 P
M/P --> 10/3
M : G : P = 10 : 6 : 3
Alternative method
----------------------
Assume 3 mangoes = 5 grapefruits = 10 pears = $1
1 M --> 1/3
1 G --> 1/5
1 P --> 1/10
M : G : P = 1/3 : 1/5 : 1/10
= 10 : 6 : 3 Multiply by 30
(Ans : 10 : 6 : 3)
3 M --> 5 G
M/G --> 5/3 = 10/6
3 M --> 10 P
M/P --> 10/3
M : G : P = 10 : 6 : 3
Alternative method
----------------------
Assume 3 mangoes = 5 grapefruits = 10 pears = $1
1 M --> 1/3
1 G --> 1/5
1 P --> 1/10
M : G : P = 1/3 : 1/5 : 1/10
= 10 : 6 : 3 Multiply by 30
Area P6 2010 SA2 Nanyang P1 Q30
The figure below is formed by stacking 4 pieces of square paper one on top of another. The papers have different prints and sizes of sides 3cm, 4cm, 5cm and 6cm. The 6-cm piece is placed at the bottom of the stack, followed by the 5-cm piece, then the 4-cm piece and the 3-cm piece is placed right on top.
Find the sum of the area A and B. (ans : 8 cm2)
6 - 1 = 5
5 - 3 = 2
6 - 4 = 2
2 x 2 = 4
4 x 2 = 8 cm2
Friday, July 30, 2010
Ratio P6 2009 SA2 P2 Nanyang Q12
Given that p : (q + r) = 1 : 3, r : (q + s) = 1 : 2 and p : s = 2 : 5.
(a) Find p : q : r : s.
(b) Find (r + q) : (p + s).
x 3
p : s = 2 : 5 = 6 : 15
x 2 x 3
p : (q + r) = 1 : 3 = 2 : 6 = 6 : 18
x 3
s + (q + r) = 5 + 6 = 11 ............... 33
x 11
r : (q + s) = 1 : 2 = 11 : 22
s = 15, (q + s) = 22, so q = 22 - 15 = 7
a) p : q : r : s = 6 : 7 : 11 : 15
b) (r + q) : (p + s) = (11 + 7) : (6 + 15)
= 18 : 21
= 6 : 7
(a) Find p : q : r : s.
(b) Find (r + q) : (p + s).
x 3
p : s = 2 : 5 = 6 : 15
x 2 x 3
p : (q + r) = 1 : 3 = 2 : 6 = 6 : 18
x 3
s + (q + r) = 5 + 6 = 11 ............... 33
x 11
r : (q + s) = 1 : 2 = 11 : 22
s = 15, (q + s) = 22, so q = 22 - 15 = 7
a) p : q : r : s = 6 : 7 : 11 : 15
b) (r + q) : (p + s) = (11 + 7) : (6 + 15)
= 18 : 21
= 6 : 7
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