Area P6 2011 PSLE Q

Decimal P6 2011 PSLE P2 Q

A fruit stall was selling pear at 70 cents each and apples at 40 cents each. Sally bought some pears and Tom bought some apples. Sally spent $1.10 more than Tom but had 7 less fruits than him.
a) How many pears did Sally buy?
b) How much did Tom spend?



0.40  x  7  =  $2.80

1.10  +  2.80  =  $3.90

0.70  -  0.40  =  $0.30

3.90  ÷  0.30  =  13  pears


a) It was  13  pears.

13  +  7  =  20

20   x  0.40  =  $8


b) It was  $8.

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Alternative solution
---------------------------

0.70 x 7 = $4.90

4.90 + 1.10  =  $6

0.70  -  0.40  =  0.30

6  ÷  0.30  =  20

20  -  7  =  13 pears


a) It was  13  pears.


20  x  0.40  =  $8


b) It was  $8.

Whole Number P6 2011 PSLE P1 Q17

A school was holding an event and tickets were sold to the teachers and pupils. Each teacher had to pay $20 each while each pupil had to pay $8 each. 1/4 of the tickets were bought by the teachers and the rest bought by the pupils. The total cost of tickets bought by the pupils was $416 more than the total cost of the tickets bought by the teachers. What was the total cost of all the tickets sold?


1  x  20  =  20

3  x  8  =  24

24 – 20  =  4 u  -->  416

                44
44 u  -->  -----  x  416  =  $4 576
                 4


It was $4 576.

Fraction P6 2011 PSLE P2 Q18

Faizal had a sum of money. He spent 1/4 of his money on a wallet and 2/5 of the remainder on a book. After that, his parents gave him $120. Finally, the ratio of the amount of money he had in the end to the amount of money he had at first was 5 : 4. What was the sum of money Faizal had at first?


        1        3
1  -  ---  =  ----
        4        4

        2        3
1  -  ---  =  ----
        5        5

 3        3         9
---  x  ----  =  ----
 5        4        20

 9
----  +  $120  -->  5 u
20

1  -->  4 u

  9           9
----  -->  ----  x  4 u  =  1.8 u
20          20

5 u  -  1.8 u  -->  $120

3.2 u  -->  $120

                4
4 u  -->  -----  x  120  =  $150
               3.2


It was $150.

--------------------------------------------------------------------------
Alternative solution
------------------------
\<---------------- 4 p --------------->|
[ | | | | ]  [ | | | | ]  [ | | | |]  [ | | | | ]
       [ | | ][ | | ] [ | | ][ | | ][ | | ][   $120   ]
                         |<----------- 5 p ----------->|

5 p  -->  9 u  +  120

4 p --> 20 u

               5
5 p  -->  ----  x  20 u  = 25 u
               4

25 u  -->  9 u  +  120

16 u  -->  120

                20
20 u  -->  ----  x  120  =  $150
                16

It was  $150.

Whole Number P6 2011 PSLE

The chairs in a hall were arranged in rows of 9 chairs each. For a concert to be held in the hall, Alex bought another 6 chairs and rearranged the chairs into rows of 7 chairs each. After the rearrangment, he found that he had 12 additional rows. How many chairs were there in the hall for the concert?

12  x  7  =  84

84  -  6  =  78

9 - 7  =  2

78  ÷  2  =  39  rows originally

39  x  9  =  351

351 + 6  =  357 chairs


It was  357  chairs.


-----------------------------------------
Alternative solution
----------------------------

9 x 1 u  -->  7 x 1 p - 6 
{1 u -- number of rows at the start; 1 p -- number of rows in the end}

9 u  -->  7 p  -  6

1 u  -->  1 p  -  12

7 u  -->  7 p  -  7 x 12  =  7 p  -  84

2 u  -->  84  -  6  =  78
1 u  -->  78  ÷  2  =  39

39  x  9  =  351

351  +  6  =  357


It was  357  chairs.

Fraction 2011 PSLE

Mr Lee has 185 more chicken pies than tuna pies. After he sold 3/5 of the chicken pies and half of the tuna pies there were 146 pies left. How many pies were sold?


5 C  -  2 T -->   185

2 C  +  1 T  -->  146

4 C  +  2 T  -->  2 x 146 =  292

9 C  -->  292  +  185  = 477

1 C  -->  477  ÷  9  =  53 

1 T  -->  146  -  2 x 53  =  40

3 C  -->  3 x  53  =  159

159  +  40  = 199


 It was 199 pies.

Speed P6 2011 PSLE

Alex and Bob were running round a 400 m circular track. Alex ran at a speed of 190 m/min while Bob ran at a speed 25 m/min slower than Alex. When Alex ran 300 m more than Bob, how many complete rounds had he run?


25 m  -->  1 min


                  300
300 m  -->  -----  x  1  =  12 min
                    25


190  x  12  =  2280 m


2280  ÷ 400 =  5.7
                    ≈  5 complete rounds


It was  5 complete rounds.

Average 2011 PSLE

The average of A, B and C  is 5y. C has 2 y more than B and A has y more than B.
a) Find B. Give your answer in terms of y.
b) If y = 5, what is B?


A [][   2 y   ]    )
B []                  ) 5 y x 3 = 15 y
C [][ y ]            )

3 u  -->  15 y  -  2 y  -  y  =  12 y

1 u --> 12 y ÷  3  =  4 y

a) It was  4 y.


4 x 5 = 20

b) It was 20.

Whole Number P6 2011 PSLE P1 Q15

Sally has a book which has 525 pages. From Monday to Thursday she reads 15 pages per day and Friday to Sunday she reads 30 pages per day. What is the least number of days she needs to finish reading the whole book?


Friday to Sunday à 30 x 3 = 90

Monday to Thursday à 15 x 4 = 60

1 set (7 days)  -->  90 + 60 = 150

525  ÷  150  =  3 sets remainder 75 pages

75 ÷ 30  =  2 r 15 days 
{So can start on Thursday, Friday or Saturday}

3  x  7  =  21

21  +  3  =  24  days


It is  24  days.