15 x 3 = 45 Squares
15 x 2 = 30 Triangles
45 + 30 = 75 cm
Alternative method
----------------------
15 x 5 = 75 cm
Showing posts with label M Area PSLE. Show all posts
Showing posts with label M Area PSLE. Show all posts
Monday, January 3, 2011
Perimeter PSLE 2010 P1 Q28
The shaded figure below is formed using 3 squares and 3 equilateral triangles. The length of the straight line AB is 15 cm. Find the perimeter of the shaded figure.
15 x 3 = 45 Squares
15 x 2 = 30 Triangles
45 + 30 = 75 cm
Alternative method
----------------------
15 x 5 = 75 cm
15 x 3 = 45 Squares
15 x 2 = 30 Triangles
45 + 30 = 75 cm
Alternative method
----------------------
15 x 5 = 75 cm
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