Angle P6 Rosyth 2011 SA2 P2 Q10

Angle PSLE 2010 P2 Q13

In the figure below, ABC is a triangle. X, Y and Z are points on the triangle such that AX=AY and YB=ZB.

If angle AYZ=104⁰ and angle XYB=107⁰, find angle ZCX.

180  -  104  =  76

180  -  76  -  76  =  38

180  -  107  =  73

180  -  73  -  73  =  34

180  -  28  -  34  =  118⁰

It is  118°.

Alternative solution provided by P6 pupil

107° + 104°  =  211°

211°  -  180°  =  31°

360°  -  31°  -  107°  -  104°  =  118°