To walk on the same side, Peter would need to walk 150 m more than Queenie first.
50 – 47 = 3 m/min
3 m --> 1 min
150 m --> 150/3 x 1 = 50 min
50 m/min x 50 min = 2500 m
2500 / 300 = 8 r 100 m
To be on the same side, Peter would need to travel another 200 m more. [since he was already 100 m on one side while Queenie was 300 m ahead (i.e. 100 m on another side of the triangle]
200 m / 50 m/min = 4 min
50 + 4 = 54 min
No comments:
Post a Comment