Thursday, July 29, 2010

Time P6

Yao has 2 clocks in his house; a cuckoo clock and a pendulam clock. Unfortunately, neither is in good working condition.The cuckoo clock gains 5 seconds for every minute it runs (which means it gets faster and faster) whilst the pendulam clock loses 5 seconds every minute it runs (which means it gets slower and slower).Yao resets both at 6 o'clock in the morning. When the time shown on the pendulam clock is 7 a.m., what time is shown on the cuckoo clock?

C: 1 min --> 1 s
1 h --> 60 x 5 = 300 s
                       = 5 min        7.05 a.m.

P: 1 min --> - 1 s
60 min --> - 60 x 5 = 300 s
                               = 5 min          6.55 a.m.

55 min --> 5 + 5 = 10 min       difference

60 min --> 60/55 x 10
            = 10 min 55 s  (rounded off to nearest s)

                  10 min 55 s
    |----------------------------------|
7.00 a.m.                         7:10:55 a.m. 
(Pendulum clock)             (Cuckoo clock)

The time shown on the cuckoo clock is 7:10:55 a.m.

2 comments:

  1. why did you divide 60 by 55? i dont understand

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  2. Sorry, there are 2 errors (1 s should be 5 s)

    Cuckoo clock moves faster while pendulum clock moves slower than actual time.

    After 55 mins, the difference between the 2 clocks is 10 min, so after 1 h (i.e. 60 min), the difference is 60/55 x 10 mins

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