A cashier had 181 pieces of $2 and $50 notes in her cash register. She took out 5/8 of the $50 notes and put in another eleven $2 notes. As a result, the number of the $2 notes was eight times the number of the $50 notes. What was the total value of her $2 and $50 notes in her cash register at first? [5 marks][Answer given: $2666]
$2 $50
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181 - 8 u 8 u
+ 11 - 5 u
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192 - 8 u 3 u
8 : 1
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192 - 8 u --> 8 x 3 u = 24 u
32 u --> 192
1 u --> 192/32 = 6
8 u --> 8 x 6 = 48
48 x 50 = $2400
181 - 48 = 133
133 x 2 = $266
2400 + 266 = $2666
It was $2666.
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