He can also alight 1 km down the road at Bus Stop B and take the 730 m Route B home.
If Tom walks at a uniform speed of 40 m/min, find:
a) the diffference in time when he alights at the two different bus stops.
b) the earliest time he can reach home if he boards the bus from the interchange 20 km away at 13 05.
Bus Stop A, Route A
800/40 = 20 min
Bus Stop B, Route B
730/40 = 18.25 min
1/30 x 60 = 2 min
18.25 + 2 = 20.25 min
20.25 - 20 = 0.25 min
= 0.25 x 60 s
=1 5 s
a) It was 15 s.
20/30 x 60 = 40 min
40 + 20 = 60 min
= 1 h
1 h
|-----------------|
1305 1405
b) It was 14 05.
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