Volume P6

A container filled with some water as shown in Figure A below has a rectangular base area of 10.4cm2. Figure B shows the same container being turned upside down.
(a) Find the capacity of the container in cm3, correct to 2 decimal places.
(b) If the water in the container is transferred to another cube-shaped container of capacity 90cm3, find the height of the water level in the cube-shaped container.

Assume 4.3 cm. [When assume other number < 4.6 cm, different volume will be obtained.]

4.6 x 10.4 = 47.84

4.3 x 10.4 = 44.72

47.84 - 44,72 = 3.12

7.8 x 10.4 = 81.12

81.12 + 3.12 = 84.24 cm3

a) It was 84.24 cm3.    < 128.96 cm3

90^(1/3) = 4.48   Not sure if this is covered in P6

47.84/90 x 4.48 = 2.38 cm

b) It was 2.38 cm.