Candle A and candle B are of the same length. Candle A, which is broader, can burn for 5 h while Candle B, the thinner candle, can burn for 4 h. If both candles are lighted at the same time, how long does it take for Candle A to be twice as long left as Candle B? [5 marks][Answer given: 3⅓ hours]
A [ H ] 5 h
B [ H ] 4 h
AN [][] (5 - T) h
BN [] (4 - T) h
AN --> (5 - T)/5 H
BN --> (4 - T)/4 H
(5 - T)/5 H --> 2 x (4 - T)/4 H
2 x (5 - T) --> 5 x (4 - T)
10 - 2 T --> 20 - 5 T
3 T --> 20 - 10 = 10
T --> 10/3 = 3 1/3 h
It is 3 1/3 h.
Alternative method (model drawing)
Since Candle B burns faster, A - 4 units used up while B 5 units used up.
A [][][][][][] 5 h
B [][][][][][] 4 h
Using B,
5/6 x 4 = 10/3
= 3 1/3 h
Or using A,
4/6 x 5 = 10/3
= 3 1/3 h
It is 3 1/3 h.
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