Yao has 2 clocks in his house; a cuckoo clock and a pendulam clock. Unfortunately, neither is in good working condition.The cuckoo clock gains 5 seconds for every minute it runs (which means it gets faster and faster) whilst the pendulam clock loses 5 seconds every minute it runs (which means it gets slower and slower).Yao resets both at 6 o'clock in the morning. When the time shown on the pendulam clock is 7 a.m., what time is shown on the cuckoo clock?
C: 1 min --> 1 s
1 h --> 60 x 5 = 300 s
= 5 min 7.05 a.m.
P: 1 min --> - 1 s
60 min --> - 60 x 5 = 300 s
= 5 min 6.55 a.m.
55 min --> 5 + 5 = 10 min difference
60 min --> 60/55 x 10
= 10 min 55 s (rounded off to nearest s)
10 min 55 s
|----------------------------------|
7.00 a.m. 7:10:55 a.m.
(Pendulum clock) (Cuckoo clock)
The time shown on the cuckoo clock is 7:10:55 a.m.
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why did you divide 60 by 55? i dont understand
ReplyDeleteSorry, there are 2 errors (1 s should be 5 s)
ReplyDeleteCuckoo clock moves faster while pendulum clock moves slower than actual time.
After 55 mins, the difference between the 2 clocks is 10 min, so after 1 h (i.e. 60 min), the difference is 60/55 x 10 mins