Alfred and Peter jogged to and fro repeatedly along a straight path in a park between two points A and B. Alfred jogged at a uniform speed of 40m/min and Peter at 60m/min. They started jogging from the opposite directions at the same time as shown below.
Alfred-----> <-------Peter
A--------------------------X-----------------Y----------------B
Distance between X and Y: 200m
They first met one another at point X. The second time they met was at point Y.
a) Find the distance between A and B.
b) If they started jogging at 0715, when did they meet again for the third time?
A1 [ ][ ][ ][ ] X
P1 [ ][ ][ ][ ][ ][ ]
DA : DP = 4 : 6 Constant Time
= 2 : 3
A2 [ ]
[ a ]
[ 10 u - a ] Y
P2 [ ]
6 u + a : 4 u + (10 u - a) = 2 : 3 Constant Time
3 x (6 u + a) = 2 x (14 u - a)
3 a + 2 a = 28 u - 18 u
5 a = 10 u
a = 2 u
4 u --> 200 m
10 u --> 10/4 x 200 = 500 m
a) The distance between A and B was 500 m.
500 x 5 = 2500 m Total distance travelled to meet the third time
40 + 60 = 100 m/min Combined speed
2500 ÷ 100 = 25 min
25 min
|--------------|
0715 0740
b) They met again for the third time at 0740.
Wednesday, July 7, 2010
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