The chairs in a hall were arranged in rows of 9 chairs each. For a concert to be held in the hall, Alex bought another 6 chairs and rearranged the chairs into rows of 7 chairs each. After the rearrangment, he found that he had 12 additional rows. How many chairs were there in the hall for the concert?
12 x 7 = 84
84 - 6 = 78
9 - 7 = 2
78 ÷ 2 = 39 rows originally
39 x 9 = 351
351 + 6 = 357 chairs
It was 357 chairs.
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Alternative solution
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9 x 1 u --> 7 x 1 p - 6
{1 u -- number of rows at the start; 1 p -- number of rows in the end}
9 u --> 7 p - 6
1 u --> 1 p - 12
7 u --> 7 p - 7 x 12 = 7 p - 84
2 u --> 84 - 6 = 78
1 u --> 78 ÷ 2 = 39
39 x 9 = 351
351 + 6 = 357
It was 357 chairs.
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