The average of A, B and C is 5y. C has 2 y more than B and A has y more than B.
a) Find B. Give your answer in terms of y.
b) If y = 5, what is B?
A [][ 2 y ] )
B [] ) 5 y x 3 = 15 y
C [][ y ] )
3 u --> 15 y - 2 y - y = 12 y
1 u --> 12 y ÷ 3 = 4 y
a) It was 4 y.
4 x 5 = 20
b) It was 20.
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