Speed P6 A002

Point P and Point Q are 40 km apart. A leopard runs from Point A to Point B at an average speed of 105 km/h. At the same time, a lion runs from Point B to Point A at an average speed of 95 km/h. How far would each animal have run when they meet on the way?



105 + 95 = 200 km/h      (Combined Speed)

40 ÷ 200 = 1/5 h     (Time for the 2 animals to meet)

105 x 1/5 = 21 km    (Distance ran by leopard)

40 – 21 = 19 km     (Distance ran by lion)

The leopard and lion would have run 21 km and 19 km respectively when they meet.


Alternative Method

DLeopard : DLion = SLeopard : DLion   (Time is a Constant; D = S x T)
                             = 105 : 95
                             = 21 : 19
 
40 u --> 40 km             (Remember to show your workings, else marks will be deducted.)
1 u --> 40 ÷ 40 = 1 km
 
21 u --> 21 km
 
19 u --> 19 km
 
The leopard and lion would have run 21 km and 19 km respectively when they meet.