A train took 12 hours to travel from Singapore to Ipoh. Its average speed for the first 1/3 of the journey was 1/2 the average speed for the remaining journey. Find the time taken for the first 1/3 of the journey.
Distance [ ][ ][ ]
Speed 1/2 S< S >
Time [ ][ ] [ ] [ ] 12 h [Each distance is 1 unit, so Time inversely proportional to Speed]
4 u --> 12 h
1 u --> 12 ÷ 4 = 3 h
2 u --> 2 x 3 = 6 h
The time taken for the first 1/3 of the journey was 6 h.
Alternative method
12 h
1/3 D 2/3 D
!-----!-----!-----!
!____!________!
1/2 S S
T1 = 1/3 D ÷ 1/2 S
= 2/3 DS
T2 = 2/3 D ÷ S
= 2/3 DS
T1 + T2 = 12 h
2/3 DS + 2/3 DS = 12 h
T1 = T2 = 12 ÷ 2 = 6 h
Time taken for the first 1/3 of the journey was 6 h.
Tuesday, June 1, 2010
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