The Lim family are great mathematicians. When asked how old everyone is, the family replies:
"Our family of 2 adults and 3 children are 100 years old together. The sum of the father's age and the son's age is 51. The father is 3 years older than the mother while the twin daughters are each 5 years younger than the brother."
What are their ages?
Firstly list out all the information (relationships) given.
Our family of 2 adults and 3 children are 100 years old together
(F + M) + (S + D1 + D2) --> 100
The sum of the father's age and the son's age is 51.
F + S --> 51
The father is 3 years older than the mother
F --> M + 3
the twin daughters are each 5 years younger than the brother
D1 = D2 --> S – 5
Then, replace D and F with S and M respectively.
(M + 3) + M + S + (S – 5) + (S – 5) --> 100
2 M + 3 S --> 100 – 3 + 5 + 5 = 107
M + S --> 51 – 3 = 48
M + 2 S --> 107 – 48 = 59
Next, solve for M or S, then follow by the other unknowns.
S --> 59 - 48 = 11
D --> 11 – 5 = 6
M --> 48 – 11 = 37
F --> 37 + 3 = 40
The father, mother, son and twin daughters are 40, 37, 11 and 6 years old respectively.
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